Good conductors of electricity Essay Example for Free

Good conductors of electricity EssayEXPERIMENTAL PROCEDURES In order to record my observations, I leave use the following guinea pigs of observation tables, and I ordain display the manner in which my telegram will be setup, in order that I will be able to experiment with them. 1. LENGTH For length, we soak up to make sure that only the length is changed, and that all the other factors are kept as a constant, i. e. the onerousness, the material, and the temperature. Thickness = 0. 3 mm Material = nichrome Temperature = fashion temperature The index is adjusted, to vary the exemption, 10 alternative readings of current and voltage are taken, at uniform intervals. For every 0. 2 volts, I will be standard the current, for each wire, and I will be observing, and recording the readings on the ammeter, in a table like this. SR. NO VOLTAGE CURRENT second-rate R= V / I IN VOLTS(V) INCREASING DECREASING CURRENT (? ) 1 0. 00 Xxx Xxx Xxx Xxx 80 X 11 2. 00 X hit AVERAGE RESISTANCE = Xxxx My expected represents will look like this. The in briefer the wire, the lesser the resistance there will be. ? = 1/ gradient ? 20 cm wire has the grea psychometric test gradient, so less resistance.The resistance on should tally with my table readings otherwise, it will mean that there is an error somewhere. 2. Thickness For thickness, we view to make sure that only the thickness is changed, and that all the other factors are kept as a constant, i. e. the length, the material, and the temperature. Length = 50 cm Material = nichrome Temperature = get on temperature SR. NO VOLTAGE CURRENT AVERAGE R= V / I IN VOLTS(V) INCREASING DECREASING CURRENT (? ).11 2. 00 X TOTAL AVERAGE RESISTANCE = Xxxx My expected graphs will look like this. The thicker the wire, the lesser the resistance there will be. ? = 1/ gradient ? 3 mm wire has the greatest gradient, so it has the least resistance. 3. Material For material, we have to make sure that only the material is changed, and that all the other factors are kept as a constant, i. e. the length, the material, and the temperature. Length = 50 cm Thickness = 0. 4 mm Temperature = room temperature SR. NO VOLTAGE CURRENT AVERAGE R= V / I IN VOLTS(V) INCREASING DECREASING CURRENT (?)TOTAL AVERAGE RESISTANCE = Xxxx My expected graphs will look like this. Different conductors have different resistances, thus, the bulls eye wire has the greatest gradient, and so it has the least resistance. In order to increase the reliability of my resulting readings, I am going to record the readings while increasing and diminish the voltage supplied. I will also make use of series and parallel circuits, to verify the law of resistance.To investigate the law of resistance for length. I will use the following type of board for this. The resistance for the 25 cm wire is shown by The resistance for the 50 cm wire is shown by This the type of graph I would be expecting to get. As you can beguile, the line for the 20+30 cm graph falls j ust a little short of the 50 cm. R = R1+ R2 In addition, to verify the law of resistivity for thickness, we use parallel circuit, which are connected in this manner Here we will test to see if the resistance of ii . 4 mm wires connected in a parallel, is equal to the resistance of a .56 mm wire.This should get me a graph like the one that follows In order to plot this type of graph, I will have to record my results in a table like this The resistance for the 0. 4 mm + 0. 4 mm wire is shown by The resistance for the 0. 56 mm wire is shown by I did a prior test, or an introductory pre experiment test, to get me used to how to know to work the rheostat, and connect the circuit, and the results I got, are on the next page.Analyzing evidence As you can see from my graphs, which are more or less like the graphs, I had expected to get, in my planning,In order to show that when the length of the wire was changed, the resistance changed proportionately, I created this turn back graph. T hus as you can see, when the lengths in crease, the resistance of the wire increases, as there are more collisions surrounded by the electron, (which is moving from the negative end to the positive), and between the atom. When length is doubled, resistance doubles. Therefore length is directly proportional to resistance. In addition, I compared the resistance obtained from the tables, when I changed the thickness of the wire, and this is the resulting pie chart.Here too, it is plain to see that when the thickness doubles, the resistance is halved. This is due to, when the thickness increases, there is more space for the electron to pass through, without colliding, and thus resistance decreases. Thus resistance is inversely proportional to resistance. Where as in my series and parallel graphs, the gradient achieved for both the graphs is almost the same, thus I state that the resistance of a longer wire, is the same as two shorter wires connected together in a series circuit. In add ition, the resistance of a thicker wire is the same as that of two thinner wires connected in a parallel.